MATH TIME!

Discussion in 'User Topics' started by Mr.Lame, Jan 9, 2018.

  1. Mr.Lame

    Mr.Lame Veteran

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    Just re-starting math after 3 years so getting the basics back! @MarkFL


    Evaluate the variable expression for x = 1, y = −2, and z = −3.
    xy − z(x − y)2

    Would it be (1 x -2) - (-3)(1-(-2))^2? Then solve? the fun stuff starts later T.T
     
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  2. MarkFL

    MarkFL Guest

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    Yes, the first step is to plug in the given numbers for the variables, as you've done. Then recall the order of operations. I would write this as:

    (1)(-2) - (-3)((1) - (-2))^2

    I would work within the parens first:

    (1)(-2) - (-3)(1 + 2)^2

    (1)(-2) - (-3)(3)^2

    Now the exponent:

    (1)(-2) - (-3)(9)

    Now the multiplications:

    -2 - (-27)

    -2 + 27

    25

    Your calculator may be able to evaluate that directly (to check your work), or you can use W|A:

    (1)(-2) - (-3)((1) - (-2))^2
     
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  3. Mr.Lame

    Mr.Lame Veteran

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    @MarkFL Thank you!!!!! I'll be getting some more for you soon! haha
     
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  4. mikeconley11

    mikeconley11 Guest

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    I wish there was a law equivalent of you
     
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  5. .:Batman:.

    .:Batman:. Guest

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    @MarkFL is a true hero :strong:
    I start back to school on the 15th and will be taking math can I ask for your help in advance? :pray:
     
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  6. MarkFL

    MarkFL Guest

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    Certainly! I will be glad to help. :)
     
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  7. mcpon14

    mcpon14 Bleeds Nexopia

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    Why don't you be that guy, lol? :)
     
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  8. .:Batman:.

    .:Batman:. Guest

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    Thank you uncle mark :rolleyes2:
     
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  9. mikeconley11

    mikeconley11 Guest

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    I'll just change my course to maths
     
  10. .:Batman:.

    .:Batman:. Guest

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    Keep at it bro :high5: we got this
     
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  11. Mr.Lame

    Mr.Lame Veteran

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    To announce, this was the correct answer !
     
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  12. MarkFL

    MarkFL Guest

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    Oh yeah!
     
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  13. mikeconley11

    mikeconley11 Guest

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    What's:

    (7x6) SU (45)= CK + 12 / MY (67)+ DI (65) - CK?
     
  14. MarkFL

    MarkFL Guest

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    That equation has no solution over the reals. ;)
     
  15. mikeconley11

    mikeconley11 Guest

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    Yes, it does
     
  16. Mr.Lame

    Mr.Lame Veteran

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    (a^5b/a^3b^-19)^2

    @MarkFL I keep getting b^16/a^4
     
  17. Mr.Lame

    Mr.Lame Veteran

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    sorry b^-9***
     
  18. MarkFL

    MarkFL Guest

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    Okay, I would write it as:

    [(a^5b)/(a^3b^(-9))]^2

    I would first work within the outer brackets, using the rule for exponents:

    x^a/x^b = x^(a - b)

    to get:

    [a^(5 - 3)b^(1-(-9))]^2

    [a^2b^10]^2

    Now square, using the rule:

    (x^a)^b = x^(ab)

    to get:

    a^(2*2)b^(10*2)

    a^4b^20

    Does that make sense?
     
  19. Mr.Lame

    Mr.Lame Veteran

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    @MarkFL

    I see I skipped to far ahead damn
     
  20. MarkFL

    MarkFL Guest

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    It's gotten to be bedtime for Bonzo here, but I will be online in the morning. :)
     
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