If you're suppose to evaluate the given quadratic expression at t = 2, then 228 is correct: 16t^2 + 80t + 4 = 4(4t^2 + 20t + 1) = 4(4(2)^2 + 20(2) + 1) = 4(16 + 40 + 1) = 4(57) = 4(50 + 7) = 200 + 28 = 228 You would only need to use the quadratic formula (or you could complete the square), if you were asked to solve the equation: 16t^2 + 80t + 4 = 0

The answer says it should be 100. I'll type it out once I drop my little one off at school. Thanks Mark

In order for the expression to equal 100, we can find the correct t by setting: 16t^2 + 80t + 4 = 100 Subtract 100 from both sides: 16t^2 + 80t - 96 = 0 Divide through by 16: t^2 + 5t - 6 = 0 Factor: (t + 6)(t - 1) = 0 Using the zero-factor property, we find the solution are: t = -6, 1 So, the values of t which make the given expression equal to 100 are t = -6 and t = 1.

You know, I should have realized that, because then it's a kinematic equation, representing the height of a projectile in feet whose initial upward velocity is 80 ft/s and whose initial height is 4 ft.

Yeah the answer is in ft too hahaha.I need to pay more attention to detail. Are you going to be on most of the day? I got a quiz tomorrow so, I may lean on you .

I'll be on for the next 4.5 hours or so, then off for 4, then I'll be back for the night. So, go ahead and post 'em up if you got 'em...

Write the exponential expression in simplest form: (x^-2y)^2(xy)^-2 so (x^4y^2)(x^-2y^-2) Then after that I'm clueless at how to get the answer, 1/x^6

OH Woah, I can't believe I didn't figure that out. So when they're in brackets like that we have to times the exponents.

@MarkFL I have 0 idea how to do this Perform the indicated operation and wire the answer in scientific notation. (4.0x10^-9)(8.4x10^5) / (3.0x10^6)(1.4x10^18) So following what we just did, does that mean we times the numerators together, then the denominators, and finish off by dividing the numbers and subtracting the 10 powers?